Friday, March 02, 2012
Fuzzy Math and politicians
"Candidates that receive 15% of the statewide vote total will be allocated delegates proportionally starting with the candidate who wins the majority of the statewide votes.”
Since Romney and Santorum were the only ones who met the threshold, and they both had similar totals, you would think that they each get 1 of the 2 voting delegates. Ahhh!! But no! See how it says “starting with the candidate”?? That’s a weird thing to see right? Well, this is how it works:
Delegate 1- Voting
Delegate 2- Voting
Delegate 3- Non-Voting
Delegate 4- Non-Voting
Delegate 5- Non-Voting
Delegate 6- Non-Voting
Delegate 7- Non-Voting
Delegate 8- Non-Voting
Delegate 9- Non-Voting
Delegate 10- Non-Voting
Delegate 11- Non-Voting
Delegate 12- Non-Voting
Delegate 13- Non-Voting
Delegate 14- Non-Voting
Yes, they each get 7 delegates. But “Starting With” means that Romney gets the first 7 and Santorum gets the next 7.
That’s got to be the worst piece of writing ever, but that’s what that’s (supposed to) mean(s).
Not that it really means anything. You need over 1000 delegates to win, so one here or there is no big deal in the grand scheme of things. Which is why it’s so much bullsh!t how the news organizations are playing this out. At stake was 1 or 2 delegates between Santorum and Romney for Michigan. That’s one-tenth of 1 percent. In baseball terms, that’s one inning of a game in May, where one team is ahead by 5 games in the standings already. ONE INNING. These outfits are allocating countless evenings to discuss the one inning in Michigan.


It’s only one delegate, but…
that is some of the most stupid logic I have seen.
Michigan awards 3 delegates to the winner of each of their 14 CDs. Then they have 14 at large delegates, split proportionally between those candidates who finish above 15% statewide. Only Romney and Santorum accomplished that, with Romney receiving 52.6% of the votes cast for all the candidates (two) who had above 15%, so he gets 7 and Santorum 7. They each have 28, plus 3 uncommitted for a total of 59.
Then they acknowledge that the state will likely lose 50% of their delegates because they had the primary before Super Tuesday. Those stricken delegates apparently still attend the convention, but don’t get to vote. In that case, there will be 2 voting delegates for the winners of each of the 14 CDs, and 2 at large to be split proportionally.
That sounds easy, but not how they did it. When awarding the at large delegates, the non voting ones were still in the pool (why? this is scenario #2). Becuase they start allocating with the highest vote getter, Romney gets both at large voting delegates, Santorum none.
It’s only one delegate, but under this logic, they could have decided to award 1 voting and 2 non-voting to the winner of each CD, and 14 voting and 14 non-voting at large, with all the 14 voting to Romney and all the 14 non-voting to Santorum.
It should be easy. When allocating voting delegates, ignore the ones who aren’t voting. Do scenario #1, full slate if no penalty is assessed, scenario #2 at 50% penalty. No need to mix the two.