Thursday, May 27, 2010
Are there clutch goalies?
Gabriel shows some data. Patrick Roy has 36 OT wins and 17 OT losses. Presuming that all goalies should be at .500, then Roy is 2.6 standard deviations from the mean. The calculation is snap: (36-17)/sqrt(36+17) = standard deviations from the mean. Sweet right? Martin Brodeur is 12-21, so he’s -1.6 SD from the mean. Those are their z-scores.
All you have to do is figure this out for all the goalies, take the standard deviation of all the z-scores, and if the result is somewhere around 1.00, then OT performance is luck.
Reason for calculation:


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